Manipulate the controls on a list page [AX 2012]

With list pages in AX 2012 where there is no code on the form. The right way is to have the code in the ListPageInteraction class. With the ListPageInteraction class – manipulating controls is a little hard because there is no obvious formRun or controls to manipulated. You can do basic enabling/disabling but not full control. Below I will show how you can get the formRun.

Below screenshot is what I had developed recently - where I added attributes dynamically to a list page. So, that it can be sorted and filtered on.

I won’t give out the full code just yet. I might do it at a later time. :-)

But I will give code snippets on how I manipulated the list page.

I created a Display menu item that calls a class to launch the list page. Then in that method I called my newly created formInitialize method.

A typical way to launch a list page through a class is like this.

formRun = SysListPageHelper::runFormWithModeledQuery(formName, querystr(MyListPage), "My new list page", _args);

If you jump into the runFormWithModeledQuery method – you will see that it uses a formRun method. Which we can control. So I simplified it by doing it myself. Just add your controls/manipulate your controls in the commented area once the formRun is initialised.

formRun = this.formInitialize(formName, "My new list page", _args, querystr(MyListPage)); 

//now that I have the formRun I can manipulated the controls  
formRun.run();
formRun.detach(); 

privatestaticFormRun formInitialize(str _formName, str _formCaption, Args _callingArgs, str _modeledQueryName = '')
{
FormRun     formRun; 

if (formName)
    {
        callingArgs.name(_formName); 

        formRun = ClassFactory::formRunClassOnClient(_callingArgs); 

if(_modeledQueryName)
        {
            formRun.modeledQueryName(modeledQueryName);
        } 

        formRun.init(); 

if (formRun && _formCaption)
        {
            formRun.design().caption(_formCaption);
        }
    } 

return formRun 
}